SOLUTION: AB and CD ARE TWO PARALLEL CHORDS OF A CIRCLE WHICH ARE ON EITHER SIDE OF THE CENTRE. SUCH THAT AB=10cm AND CD=24cm FIND THE RADIUS IF THE DISTANCE BETWEEN AB AND CD IS 17cm.

Algebra ->  Pythagorean-theorem -> SOLUTION: AB and CD ARE TWO PARALLEL CHORDS OF A CIRCLE WHICH ARE ON EITHER SIDE OF THE CENTRE. SUCH THAT AB=10cm AND CD=24cm FIND THE RADIUS IF THE DISTANCE BETWEEN AB AND CD IS 17cm.       Log On


   



Question 1071992: AB and CD ARE TWO PARALLEL CHORDS OF A CIRCLE WHICH ARE ON EITHER SIDE OF THE CENTRE. SUCH THAT AB=10cm AND CD=24cm FIND THE RADIUS IF THE DISTANCE BETWEEN AB AND CD IS 17cm.

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!



Draw the two red radii:



This splits the green line, which is 17cm in two parts,
x and y, so

x+%2B+y%22%22=%22%2217

and we solve it for y:

y%22%22=%22%2217-x

The green line splits the two chords, which are 10cm
and 24cm, in half, 5cm and 12cm:

And we have two right triangles.  We use the Pythagorean theorem on
both right triangles:

x%5E2%2B5%5E2=r%5E2 and y%5E2%2B12%5E2=r%5E2

So

x%5E2%2B25=r%5E2 and y%5E2%2B144=r%5E2

x%5E2%2B25=y%5E2%2B144

x%5E2-y%5E2=119

And since y%22%22=%22%2217-x

x%5E2-%2817-x%29%5E2=119

x%5E2-%28289-34x%2Bx%5E2%29=119



x=12

Substitute in

x%5E2%2B25=r%5E2

12%5E2%2B25=r%5E2

144%2B25=r%5E2

169=r%5E2

sqrt%28169%29=r

13=r

So the radius of the circle is 13.

Edwin