SOLUTION: Two ships leave at the same time , ship x is heading due north and ship Y is heading due east. Twelve hours later they are 600 miles apart. If the ship X Had travels 480 miles from

Algebra ->  Pythagorean-theorem -> SOLUTION: Two ships leave at the same time , ship x is heading due north and ship Y is heading due east. Twelve hours later they are 600 miles apart. If the ship X Had travels 480 miles from      Log On


   



Question 1071007: Two ships leave at the same time , ship x is heading due north and ship Y is heading due east. Twelve hours later they are 600 miles apart. If the ship X Had travels 480 miles from the port , how many miles will ship Y travel?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Two ships leave at the same time ,
ship x is heading due north and ship Y is heading due east.
Twelve hours later they are 600 miles apart.
If the ship X Had travels 480 miles from the port , how many miles will ship Y travel?
:
This is a pythag problem where each leg is the distance traveled by each ship and the 600 mi between them is the hypotenuse
let y = distance traveled by ship y
y^2 + 480^2 = 600^2
y^2 + 230400 = 360000
y^2 = 360000 - 230400
y^2 = 129600
y = sqrt%28129600%29
y = 360 mi traveled by ship y
:
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Confirm this on your calc; enter sqrt%28360%5E2%2B480%5E2%29