SOLUTION: A piece of rope was cut into 2 parts such that the lengths of the two are in the ratio 5:6.If one piece was linger by 10m,how long was each piece?

Algebra ->  Pythagorean-theorem -> SOLUTION: A piece of rope was cut into 2 parts such that the lengths of the two are in the ratio 5:6.If one piece was linger by 10m,how long was each piece?      Log On


   

Question 1062642: A piece of rope was cut into 2 parts such that the lengths of the two are in the ratio 5:6.If one piece was linger by 10m,how long was each piece?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the length of the shorter piece in meters
+x+%2B+10+ = the length of the longer piece in meters
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+5%2F6+=+x%2F%28+x+%2B+10+%29+
+5%2A%28+x+%2B+10+%29+=+x%2A6+
+5x+%2B+50+=+6x+
+x+=+50+
and
+x%2B+10+=+60+
The shorter piece is 50 m
The longer piece is 60 m
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check:
+5%2F6+=+50%2F60+
+5%2F6+=+5%2F6+
OK