SOLUTION: two legs are x+2 but the hypotenuse is x-2 and x+6 How do you solve this

Algebra ->  Pythagorean-theorem -> SOLUTION: two legs are x+2 but the hypotenuse is x-2 and x+6 How do you solve this      Log On


   

Question 1034049: two legs are x+2
but the hypotenuse is x-2 and x+6
How do you solve this
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
This is not really clear. Do you mean the hypotenuse is (x-2)+(x+6) or (x-2)(x+6)?
If either one, we substitute into
a%5E2+%2B+b%5E2+=+c%5E2
and solve for x...
Please repost...