SOLUTION: Suppose one leg and the hypotenuse of a right triangle are consecutive integers. Find the length of the leg and hypotenuse if the other leg is of length 7cm.
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Question 1031354: Suppose one leg and the hypotenuse of a right triangle are consecutive integers. Find the length of the leg and hypotenuse if the other leg is of length 7cm. Found 3 solutions by stanbon, ikleyn, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose one leg and the hypotenuse of a right triangle are consecutive integers. Find the length of the leg and hypotenuse if the other leg is of length 7cm.
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leg:: x
hypot:: 2x
leg:: 7 cm
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(2x)^2 = x^2 + 49
3x^2 = 49
x^2 = 49/3
x = 7/sqrt(3) = (7/3)sqrt(3) cm
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Cheers,
Stan H.
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You can put this solution on YOUR website! .
Suppose one leg and the hypotenuse of a right triangle are consecutive integers. Find the length of the leg and hypotenuse if the other leg is of length 7cm.
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Leg :: x
Hypotenuse :: x + 1
Other leg :: 7.
Pythagorean equation:
= .
= ,
= ,
2x = 48,
x = = 24.
Answer. Two legs are 24 and 7 units long. The hypotenuse is 25 units long.
Check. = 625 = .
You can put this solution on YOUR website!
Suppose one leg and the hypotenuse of a right triangle are consecutive integers. Find the length of the leg and hypotenuse if the other leg is of length 7cm.
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