SOLUTION: Shorter leg of a right triangle is 7ft shorter than the longer leg. The hypotenuse is 7ft longer than the longer leg. Find the side lengths of the triangle. I cant seem to ge

Algebra ->  Pythagorean-theorem -> SOLUTION: Shorter leg of a right triangle is 7ft shorter than the longer leg. The hypotenuse is 7ft longer than the longer leg. Find the side lengths of the triangle. I cant seem to ge      Log On


   



Question 1013986: Shorter leg of a right triangle is 7ft shorter than the longer leg.
The hypotenuse is 7ft longer than the longer leg.
Find the side lengths of the triangle.
I cant seem to get my head around this.
(x-7^2)+(x+7^2)=?? Sorry, pretty fresh to this.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Shorter leg of a right triangle is 7ft shorter than the longer leg.
The hypotenuse is 7ft longer than the longer leg.
Find the side lengths of the triangle.
I cant seem to get my head around this.
(x-7^2)+(x+7^2)=?? Sorry, pretty fresh to this.
Let the length of the longer leg, be L
Then the length of the shorter leg is: L - 7, and length of hypotenuse is: L + 7
Using Pythagorean theorem: a%5E2+%2B+b%5E2+=+c%5E2, we get: L%5E2+%2B+%28L+-+7%29%5E2+=+%28L+%2B+7%29%5E2
Can you now solve this for L, the longer leg, and subsequently, the shorter leg and the hypotenuse?
If not, say so, and you might get further help!