Tutors Answer Your Questions about Proofs (FREE)
Question 1079556: Can you help me with this assignment in analytic geometry:
The segment joining (2,-4) and (9,3) is divided into two segments, one of which is ¾ as long as the other. Find the point of division.
I need a complete solution. Can you graph it. Thank you!
Click here to see answer by Edwin McCravy(20054)  |
Question 1079557: Can you help me with this assignment in analytic geometry:
Show that each of the points are the vertices of a rectangle
L ( -4,3); M (0,-2); N(5,2); O (1,7)
I need a complete solution. Can you graph it. Thank you!
Click here to see answer by Boreal(15235)  |
Question 1080223: I need help with this mathematical induction to show that the given statement is true for all natural numbers,
3 + 5 + 7 +...+ (2n+1) = n(n+2)
So far I have the following:
Prove Basis n=1
n(n+2)
= 1(1+2)
= 3
Therefore the statement is true for n=1.
When n=k assume
3 + 5 + 7 +...+ (2n+1) = n(n+2)
replace n with k
3 + 5 + 7 +...+ (2k+1) = k(k+2)
Then n = k+1 must be proven, meaning replace k terms with (k+1)
---------------------------------------------------------------------------------
This is where I get lost, I don't know where/how I should replace with (k+1) despite how simple it sounds
I get
3 + 5 + 7 +...+ (2(k+1)+1) = (k+1)((k+1)+2)
But some sites show a funky set up where the right/first part of the equation gets another (k+1) replacement but don't explain how. I'm sure the left hand side (k+1)((k+1)+2) is correct. I know that after that step you must replace the 3 + 5 + 7 ... etc. but I can't get that far since I'm stuck on the (k+1) replacement! Any help/advice is appreciated and I don't need it solved just some guidance! Thank you!
Click here to see answer by jim_thompson5910(35256) |
Question 1080517: Using mathematical induction, show its true for all natural #'s n
+ =
So far I got
Proof n=1
= 
1 = 3/3
1 = 1
so its true for n=1
next assume n = k, so
+ =
then we must prove n = k+1
+ + =
we do some replacing with our n = k
+ =
we have our left hand side that we must match to our right hand side, but this is where my math get's messy when I go to simplify,
+ =
+ =
now I'm left with a +4k^2 and I'm unsure what method to use here, or maybe I did the first steps wrong? If I factor the k(2k-1)(2k+1) I get a 4k^3-k and I thought maybe multiply by (3/3) to get everything as denominator of 3, but it doesn't really help me understand what I should do next for certain. Any help would be greatly appreciated
Click here to see answer by ikleyn(52775)  |
Question 1083625: P ∙ (Q ⊃ R) ; (P ∙ Q) ⊃ (P ∙ R)
are logically equivalent to each other, or whether they are contradictory to each other by making a truth table for them. If they are neither of those, determine whether they are consistent with each other, or whether they are inconsistent with each other
Click here to see answer by jim_thompson5910(35256) |
Question 1101171: Construct proofs to show that the following arguments are valid.
1.(AvG)>K
2.K>(B>F)
3.A.B ... (Conclusion is triple dot) F
So far I've got
4. (AvG)>(B>F) 1,2 Hypothetical syllogism
5. B 3, Simplification
6. A 3, Simplification
I have to prove how F is the conclusion.
Click here to see answer by Edwin McCravy(20054)  |
Question 1101290: Today I asked my Professor in my Logic class if I could do this.
1. ~P
2. ~(PvQ)>~R
3. ~Q ...(conclusion) ~R
4. ~Pv~Q 1,Add
5. ~R 2,1 MP
He flipped out and asked how in the world did I got this because ~Pv~Q is not the same as ~(PvQ). He very rudely told me I should know this by now. Which I obviously don't and was curious why those are not equivalent and if they ever would be equivalent. Also, what would be the way to solve this proof then?
Click here to see answer by jim_thompson5910(35256) |
Question 1102118: I’m doing homework concerning the rules of replacement. We are allowed to use 8 rules of implication (modus ponens, modus tollens, pure hypothetical syllogism, disjunctive syllogism, constructive dilemma, simplification, conjunction, and addition) and 10 rules of replacement (De Morgan’s rule, commutativity, associativity, distribution, double negation, transposition, material implication, material equivalence, exportation, and tautology). I have been stuck on the same proof for several days, trying different solutions for multiple hours each day. The problem is as follows:
Premise 1: If Q, then (A and V)
Premise 2: If (If not V, then C), then B
Conclusion: If Q, then B
Even a nudge in the right direction would be appreciated. Thank you.
Click here to see answer by jim_thompson5910(35256) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485
|