SOLUTION: I need help completing this proof. 1. R&S, S->(P->Q), Q->P |- P<->Q
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Question 633618
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I need help completing this proof.
1. R&S, S->(P->Q), Q->P |- P<->Q
Answer by
solver91311(24713)
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You can
put this solution on YOUR website!
Premise
Premise
Premise
Prove:
From 1 by Conjunction Elimination
From 2 by Modus Ponens
From 3 and 5 by Biconditional Introduction
John
My calculator said it, I believe it, that settles it