SOLUTION: A student claims that the equation the !-x = 3 (square root of) has no solution, since the square root of a negative number does not exist. Why is this argument wrong? (The teache

Algebra ->  Proofs -> SOLUTION: A student claims that the equation the !-x = 3 (square root of) has no solution, since the square root of a negative number does not exist. Why is this argument wrong? (The teache      Log On


   

Question 259397: A student claims that the equation the !-x = 3 (square root of) has no solution, since the square root of a negative number does not exist. Why is this argument wrong? (The teacher do NOT want to solve this equation, she just wants to know why is the argument wrong)
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
The square root of -1 is i. It is called an imaginary number.
BTW sqrt(-3)
sqrt%28-3%29