Question 122289This question is from textbook Mechanics I
: I didnt know what topic this stuff came under, :( so i thought proof maybe....the closest i can find, its a mechanics question.
11. A parcel of mass 60kg is released from rest on a smooth plane inclined at arcsin 0.6 (3/5) to the horizontal. Find the velocity of the parcel when it has travelled 5m down the slope.
I cant do it, can some one help?
What i personally did was,
invsin0.6 = 37, Sin37*9.81*60 = 354 approx.
So Acceleration down the slope is 354ms-2,
v squared = u sqaured + 2as,
so, velocity squared therefore =, 2 * 354 * 5 = 3540, root that = velocity, =59.5...
but the answer is 7.67 :( Please help? with details of how to do, thanks.
This question is from textbook Mechanics I
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! not sure why you included the mass in the calculation? __ there is no mention of friction...
the acceleration along the incline is g*sin(a)
__ where a is the angle of inclination and g is the gravitational acceleration
using .6g as the acceleration will give you the proper result
the rest of your work is fine
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