SOLUTION: Please help with this questions, prove by induction that the formulas positive integral n.
1) 1+4+7+...+(3n-2)= ½n(3n-1)
2) 1+5+9+...+(4n-3)=n(2n-1)
3) 5+10+15+...+5n=5/2n(n+1)
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-> SOLUTION: Please help with this questions, prove by induction that the formulas positive integral n.
1) 1+4+7+...+(3n-2)= ½n(3n-1)
2) 1+5+9+...+(4n-3)=n(2n-1)
3) 5+10+15+...+5n=5/2n(n+1)
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Question 1190618: Please help with this questions, prove by induction that the formulas positive integral n.
1) 1+4+7+...+(3n-2)= ½n(3n-1)
2) 1+5+9+...+(4n-3)=n(2n-1)
3) 5+10+15+...+5n=5/2n(n+1)
4) 1²+3²+5²+....+(2n-1)²=1/3n(4n²-1)
5) 1+2+4+8+....+2^n-1=2^n-1 Answer by ikleyn(52778) (Show Source):
