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Let "a" be such an integer number that 20a ≡ 2 (mod 8)
It means that 20a - 2 is divisible by 8:
20a-2 = 8m for some integer m (1)
Divide by 2 both sides of equation (1). You will get then
10a - 1 = 4m.
But it is just a contradiction: 10a is a multiple of 2; 4m is a multiple of 2;
hence, their difference 1 = 10a - 4m must be multiple of 2, but it is not the case.
The contradiction proves that 20a ≡ 2 mod 8 is not possible.