SOLUTION: Derive the base-to-height ratio equation from lecture 11:
B/H' = (1-PE/100)d/f
Use similar triangle relationships, starting with G/H' = d/f. Symbol definitions are given in
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-> SOLUTION: Derive the base-to-height ratio equation from lecture 11:
B/H' = (1-PE/100)d/f
Use similar triangle relationships, starting with G/H' = d/f. Symbol definitions are given in
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Question 1176033: Derive the base-to-height ratio equation from lecture 11:
B/H' = (1-PE/100)d/f
Use similar triangle relationships, starting with G/H' = d/f. Symbol definitions are given in the PPT, the figure will be helpful. Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website! Derive the base-to-height ratio equation from lecture 11:
B/H' = (1-PE/100)d/f
Use similar triangle relationships, starting with G/H' = d/f. Symbol definitions are given in the PPT, the figure will be helpful.
