SOLUTION: 1. W ⊃ (P v C) 2. ~P 3. W/C I am trying to see how they were able to get the conclusion "C" I think it should be 4. C modus ponens 1,2 But I am not sure if that

Algebra ->  Proofs -> SOLUTION: 1. W ⊃ (P v C) 2. ~P 3. W/C I am trying to see how they were able to get the conclusion "C" I think it should be 4. C modus ponens 1,2 But I am not sure if that       Log On


   



Question 1171806: 1. W ⊃ (P v C)
2. ~P
3. W/C
I am trying to see how they were able to get the conclusion "C"
I think it should be
4. C modus ponens 1,2
But I am not sure if that is correct or if i am on the wrong path.

Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

You have the right idea, but it will require two steps instead of one.

You can use Modus Ponens on lines 1 & 3 getting P v C as the result.
This is because we're told that "If W, then (P v C)" on line 1 and we know that W is the case on line 3. So that must mean (P v C) is the case as a result.

Afterward, we use disjunctive syllogism on the statements P v C and ~P (line 2)
Basically from P v C we know that either P is the case or C is. But line 2 says that ~P is the case, so we know that P isn't the case. That leaves C being the conclusion.

Here's the derivation table of the proof argument
NumberStatementLines UsedReason
1W -> (P v C)
2~P
3W
:.C
4P v C1,3Modus Ponens
5C4,2Disjunctive Syllogism