SOLUTION: (K->L)&(K->M)├ K->(L&M)

Algebra ->  Proofs -> SOLUTION: (K->L)&(K->M)├ K->(L&M)      Log On


   

Question 1153481: (K->L)&(K->M)├ K->(L&M)
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!


1.  (K->L)&(K->M)



2.  (~KvL)&(~KvM)        1, material implication



3.  ~Kv(L&M)             2, distribution



4.   K->(L&M)            3, material implication





Edwin