SOLUTION: Simplify the lefthandside so that LHS=RHS
2/sin(b) = sin(b)/cos(b)-1 + sin(b)/cos(b)+1
This is a trig identity and I have no clue how to reach my goal on the left-hand side.
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-> SOLUTION: Simplify the lefthandside so that LHS=RHS
2/sin(b) = sin(b)/cos(b)-1 + sin(b)/cos(b)+1
This is a trig identity and I have no clue how to reach my goal on the left-hand side.
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Question 1112838: Simplify the lefthandside so that LHS=RHS
2/sin(b) = sin(b)/cos(b)-1 + sin(b)/cos(b)+1
This is a trig identity and I have no clue how to reach my goal on the left-hand side.
because resolving the ambiguities any other way doesn't make any sense. The problem is that the above equation, while it may have a non-null solution set, is not, under any possible definition of the word, an "identity". An identity is a statement that is true for all possible values of the variable.
As a counter-example to your assertion that this is an identity let . Then:
Since and the statement becomes
Which is to say:
Buzz! Sorry, wrong answer. Thank you for playing.
You also have a big problem if or , since either one of those values gives you a zero denominator in the RHS.
So either you wrote the problem incorrectly or your instructor is giving you a trick question. However, no one should have ever referred to what you wrote as an "identity".
John
My calculator said it, I believe it, that settles it
Hello, John
when you start your posts with the line
font face="Times New Roman" size="+2"
can you PLEASE then "neutralize" this statement at the end of your post;
otherwise the action of this operator spreads to the next post (to the other posts).
Thank you . . .