1. P—>A Premise
2. X—>B Premise
3. (P v X) —> (A v B) This follows directly by Constructive Dilemma (CD)
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I think this proves it the long way…
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1. P—>A Premise
2. X—>B Premise
3. P v X Premise
::4. P Assumption, start Conditional Proof (CP)
::5. A 4,1 Modus Ponens (MP)
::6. A v B 5 Addition (ADD)
::7. X Assumption
::8. B 7,2 MP
::9. A v B 8 ADD
10. A v B 1,2,3 Proof By Cases (PBC) { Discharges CP assumptions }
11. (P v X) —> (A v B) 1,2 CP