Question 1052276: Hi I'm kind of stuck on this:
We have seven different pairs of shoes, and eight different pairs of socks.
(a) How many ways are there to pick a pair of shoes and a pair of socks?
for this I think its just 7 choose 1 * 8 choose 1
= 56
(b) How many ways are there to pick a pair of shoes and two socks, not necessarily from
the same pair? (Socks in the same pair are identical, but socks from different pairs are
different.)
How would I go about this what I have so far is 7 choose 1 * 16 choose 2 * 15 choose 1
= 12600
It seems like too large a jump?
Thanks
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! 7*8 = 56
Here's proof
Shoes: A,B,C... G (7)
Socks: 1,2,3... 8
------------------------------
A1 A2 A3 A4 A5 A6 A7 A8
B1 B2 B3 B4 B5 B6 B7 B8
C1 C2 C3 C4 C5 C6 C7 C8
D1 D2 D3 D4 D5 D6 D7 D8
E1 E2 E3 E4 E5 E6 E7 E8
F1 F2 F3 F4 F5 F6 F7 F8
G1 G2 G3 G4 G5 G6 G7 G8
Choices: 7 down and 8 across, 7*8 = 56
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