SOLUTION: Complex numbers If z=rcis(theta) FIND: |iz^2| I am confused about how I incorporate the i into the absolute value. I can't remember what it means. Please help and show exact

Algebra ->  Proofs -> SOLUTION: Complex numbers If z=rcis(theta) FIND: |iz^2| I am confused about how I incorporate the i into the absolute value. I can't remember what it means. Please help and show exact      Log On


   

Question 1047975: Complex numbers
If z=rcis(theta) FIND: |iz^2|
I am confused about how I incorporate the i into the absolute value. I can't remember what it means. Please help and show exactly how I complete the workings. I can easily find the absolute value of z^2 I just really don't understand how to put the i into it.
Thank you!!
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
If z = a + bi, then iz = i*(a + bi) = ai + b*(i^2) = -b + ai.

So, iz is the complex number with the real part -b and the imaginary part ai.

Can you proceed from this point on your own?


There is a bunch of my lessons on complex numbers
    - Complex numbers and arithmetical operations on them
    - Complex plane
    - Addition and subtraction of complex numbers in complex plane
    - Multiplication and division of complex numbers in complex plane
    - Raising a complex number to an integer power
    - How to take a root of a complex number
    - Solution of the quadratic equation with real coefficients on complex domain
    - How to take a square root of a complex number
    - Solution of the quadratic equation with complex coefficients on complex domain

    - Solved problems on taking roots of complex numbers
    - Solved problems on arithmetic operations on complex numbers
    - Solved problem on taking square root of complex number
    - Miscellaneous problems on complex numbers
in this site.