SOLUTION: Find three consecutive integers such that three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.

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Question 997903: Find three consecutive integers such that three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let n (n+1) & (n+2) be the numbers
3(n+2) +2 = 5(n) +3(n+1)

3n+6 +2 = 5n+3n+3
3n+8 =8n+3
5n =5
n =1
1,2,3 are the numbers