SOLUTION: Find two consective odd intergers whose sum is 116.

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Question 99718: Find two consective odd intergers whose sum is 116.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Consecutive odd integers follow the form: 2x%2B1, 2x%2B3, 2x%2B5, ...., etc


So the sum of two consecutive odd integers is:


%282x%2B1%29%2B%282x%2B3%29=116




2x%2B1%2B2x%2B3=116 Start with the given equation


4x%2B4=116 Combine like terms on the left side


4x=116-4Subtract 4 from both sides


4x=112 Combine like terms on the right side


x=%28112%29%2F%284%29 Divide both sides by 4 to isolate x



x=28 Divide

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Answer:
So our answer is x=28






Since x=28, our first number is


2%2828%29%2B1=57

So our first number is 57


and our second number is


2%2828%29%2B3=59

So our second number is 59



So our two numbers are 57 and 59



Check:


57%2B59=116

116=116 works