SOLUTION: 1. Sum= 57 Product= 6732. 2. Sum= 43 Product= 2160 3. Sum= 49 Product= 575 Note: 3 numbers each time; a•b•c; a+b+c; Find the 3 numbers

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: 1. Sum= 57 Product= 6732. 2. Sum= 43 Product= 2160 3. Sum= 49 Product= 575 Note: 3 numbers each time; a•b•c; a+b+c; Find the 3 numbers       Log On


   



Question 960340: 1. Sum= 57 Product= 6732.
2. Sum= 43 Product= 2160
3. Sum= 49 Product= 575
Note: 3 numbers each time; a•b•c; a+b+c;
Find the 3 numbers

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1. Sum= 57 Product= 6732.
2. Sum= 43 Product= 2160
3. Sum= 49 Product= 575
Note: 3 numbers each time; a•b•c; a+b+c;
Find the 3 numbers
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These are trial and error problems, there's no algebraic solution.
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Sum= 57 Product= 6732
The product is even, so at least 1 number is even.
The sum is odd, so either 1 number is odd, or 3 are odd --> 2 even #'s and 1 odd.
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Factor 6732 = 2*2*3*3*11*17
Try combinations using all the factors to get a sum of 57.
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