SOLUTION: find 3 consecutive odd integers such that the sum of the three numbers is 60 less than the square of the largest integer.

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Question 956498: find 3 consecutive odd integers such that the sum of the three numbers is 60 less than the square of the largest integer.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
n=first integer; n+2=second integer; n+4=third integer
n%2B%28n%2B2%29%2B%28n%2B4%29=%28n%2B4%29%5E2-60
3n%2B6=n%5E2%2B8n%2B16-60 Subtract (3n+6) from each side.
0=n%5E2%2B5n-50
%28n-5%29%28n%2B10%29=0
n-5=0 or n+10=0
n=5 or n=-10 ANSWER 1: The first integer is 5.
n+2=5+2=7 ANSWER 2: The second integer is 7.
n+4=5+4=9 ANSWER 3: The third integer is 9.
CHECK:
5%2B7%2B9=9%5E2-60
21=81-60
21=21