SOLUTION: The Johnson family is building a dog house. The total floor-surface are will be 24sq. ft if the length is 6 more than three times the width, what is the width of the dog house?
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-> SOLUTION: The Johnson family is building a dog house. The total floor-surface are will be 24sq. ft if the length is 6 more than three times the width, what is the width of the dog house?
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Question 949244: The Johnson family is building a dog house. The total floor-surface are will be 24sq. ft if the length is 6 more than three times the width, what is the width of the dog house? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! W=width; L=length=3W+6; A=L*W=24 sq ft
A=L*W Substitute for L Divide each side by 3 Subtract 8 sq ft from each side
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=36 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 2, -4.
Here's your graph:
Here we need the positive answer, so ANSWER 1: The width is 2 feet.
L=3W+6 feet=3(2 feet)+6 feet=6 feet+6 feet=12 feet ANSWER 2: the length is 12 feet
CHECK:
Area is 24 sq ft
24 sq ft=L*W
24 sq ft=12 feet*2 feet
24 sq ft=24 sq ft