SOLUTION: The product of two consecutive integers is 11 less than the square of the lesser integer. Find the greater of the two integers

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Question 948889: The product of two consecutive integers is 11 less than the square of the lesser integer. Find the greater of the two integers
Answer by macston(5194) About Me  (Show Source):
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The product of two consecutive integers is 11 less than the square of the lesser integer. Find the greater of the two integers
x=lesser integer; x+1=greater integer
%28x%29%28x%2B1%29=x%5E2-11
x%5E2%2Bx=x%5E2-11 Subtract x%5E2 from each side
x=-11 The lesser integer is -11
x+1=-11+1=-10 ANSWER: The greater integer is -10
CHECK:
%28-11%29%28-10%29=%28-11%29%5E2-11
110=121-11
110=110