SOLUTION: The sum of four consecutive integers decreased by 18 is greater than twice the smallest of the four. What are the four smallest such integers?

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Question 935614: The sum of four consecutive integers decreased by 18 is greater than twice the smallest of the four. What are the four smallest such integers?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
four consecutive integers can be expressed as x, x%2B1, x%2B2,x%2B3 where x is the smallest of the four
if the sum of four consecutive integers decreased by 18 is greater than twice the smallest of the four, we have
x%2Bx%2B1%2Bx%2B2%2Bx%2B3-18%3E2x
4x%2B6-18%3E2x
4x-12%3E2x
4x-2x%3E12
2x%3E12
x%3E6
integers are: 7,8,9,10
check:
7%2B8%2B9%2B10-18%3E2%2A7
34-18%3E14
16%3E14