SOLUTION: $5400 is invested, part of it at 12% and part of it at 8%. For a certain year, the total yield is $ 552.00. How much was invested at each rate?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: $5400 is invested, part of it at 12% and part of it at 8%. For a certain year, the total yield is $ 552.00. How much was invested at each rate?      Log On


   

Question 934808: $5400 is invested, part of it at 12% and part of it at 8%. For a certain year, the total yield is $ 552.00. How much was invested at each rate?
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
x = amount invested at 12%
y = amount invested at 8%
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x + y = 5400
0.12x + 0.08y = 552
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put the system of linear equations into standard form
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x + y = 5400
0.12x + 0.08y = 552
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copy and paste the above standard form linear equations in to this solver:
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solution:
x = amount invested at 12% = 3000
y = amount invested at 8% = 2400
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