Question 931872: Find 3 consecutive positive odd integers such that the product of the first and second integers is eight more than the third integer.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! z = y + 2
y = x + 2
xy = z + 8
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z = (x + 2) + 2
z = x + 4
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xy = z + 8
x(x + 2) = z + 8
x(x + 2) = (x + 4) + 8
xx + 2x = x + 12
xx + x - 12 = 0
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the above quadratic equation is in standard form, with a=1, b=1 and c=-12
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 1 -12
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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x = 3
x = -4
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the negative root doesn't fit the problem statement, so use the positive root:
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answer:
x = 3
y = 5
z = 7
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