SOLUTION: The sum of four consecutive intergers is 8 less than 6 times the first interger

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Question 917994: The sum of four consecutive intergers is 8 less than 6 times the first interger
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: x, (x+1), (x+2), (x+3)

x + (x+1) + (x+2) + (x+3) = 6x - 8
4x + 6 = 6x - 8
14 = 2x
x = 7

The integers are 7, 8, 9, and 10.