SOLUTION: find three consecutive integers such that 7 decreased by the third is 75 more than twice the second

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Question 904977: find three consecutive integers such that 7 decreased by the third is 75 more than twice the second
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

7- (x+1) = 75 + 2x
-x + 6 = 2x + 75
-3x = 69
x = -23

The integers are -24, -23, and -22.