SOLUTION: if the larger of two integers whose sum is 88 is divided by the smaller the quotient is 5 and the remainder is 10. what are the 2 nos.?

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Question 89899: if the larger of two integers whose sum is 88 is divided by the smaller the quotient is 5 and the remainder is 10. what are the 2 nos.?
Found 2 solutions by stanbon, ankor@dixie-net.com:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
if the larger of two integers whose sum is 88 is divided by the smaller the quotient is 5 and the remainder is 10. what are the 2 nos.?
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Let the two integers be x and 88-x
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EQUATION: (88-x)/x = 5 + 10/(x
Multiply thru by x to get:
88-x = 5x + 10
6x = 78
x= 13 (one of the numbers)
88-x= 75 (the other number)
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Cheers,
Stan H.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
if the larger of two integers whose sum is 88 is divided by the smaller the quotient is 5 and the remainder is 10. what are the 2 nos.?
:
x + y = 88
y = (88 - x)
:
%28%28x-10%29%29%2Fy = 5
:
Multiply equation by y
x-10 = 5y
:
Substitute (88-x) for y:
x - 10 = 5(88-x)
:
x - 10 = 440 - 5x
:
x + 5x = 440 + 10
:
6x = 450
:
x = 75
:
y = 88 - 75 = 13
:
:
Check: Divide 75 by 13 you get 5 with a remainder of 10