SOLUTION: Find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three times the fourth equals three.
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: Find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three times the fourth equals three.
Log On
Question 894146: Find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three times the fourth equals three. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Find four consecutive even integer
x, (x+2), (x+4),(x+6)
:
such that the sum of twice the first, five times the second, and four times the third divided by three times the fourth equals three. = 3
multiply both sides by 3(x+6)
2x + 5(x+2) + 4(x+4) = 3(3(x+6))
Distribute
2x + 5x + 10 + 4x + 16 = 9x + 54
11x + 26 = 9x + 54
11x - 9x = 54 - 26
2x = 28
x = 28/2
x = 14 is the 1st integer, 16, 18, 20 are the rest
:
;
See if that works = = = 3
