SOLUTION: find four consecutive integers such that twice the sum of the first, second, and fourth is 40 less than 3 times the opposite of the third

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Question 893802: find four consecutive integers such that twice the sum of the first, second, and fourth is 40 less than 3 times the opposite of the third
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The integers, n, n+1, n+2, n+3.
2%28n%2B%28n%2B1%29%2B%28n%2B3%29%29=-40%2B3%28-%28n%2B2%29%29, description transcribed into equation;

2%283n%2B4%29=-40-3%28n%2B2%29
6n%2B8=-40-3n-6
9n%2B8=-40-6
9n%2B8=-46
9n=-46-8
9n=-54
n=-54%2F9
highlight%28n=-6%29, and you can find next ones: -5, -4, -3.