SOLUTION: A farmer wants to enclose a rectangular lot of using 48 meters of fencing materials. If the wall acts as one side of the fence, what is the maximum area that can be fenced?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: A farmer wants to enclose a rectangular lot of using 48 meters of fencing materials. If the wall acts as one side of the fence, what is the maximum area that can be fenced?      Log On


   

Question 892291: A farmer wants to enclose a rectangular lot of using 48 meters of fencing materials. If the wall acts as one side of the fence, what is the maximum area that can be fenced?
Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
length = L
width = W

Assuming the wall is one length, then we have 2W + L = 48. This is maximized when W = L.

x = side length
3x = 48
x = 16

area = x^2 = 256 m^2

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.


            The answer and the solution by @ThePenguin are both incorrect.



The correct answer is 12*24 = 288 square meters for the area.

The optimum dimensions are 12 m width and 24 meters length (along the wall).

See the lesson
    - A farmer planning to fence a rectangular area along the river to enclose the maximal area
in this site.