Question 859570: It would be greatly appreciated if you helped me with:
Find three consecutive, positive, even integers such that the product of the second and the third is 80.
I've attempted at:
(x)(x+2)(x+4)=80
Thanks for the help!
Found 2 solutions by ewatrrr, josmiceli:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
three consecutive, positive, even integers: (x),(x+2),(x+4) Yes!
Question States***product of the second and the third is 80.
(x+2)(x+4)=80
x^2 + 6x - 72 = 0
(x + 12)(x- 6) = 0, x = 6 (tossing out negative solution)
the three consecutive, positive, even integers are: 6, 8, 10
Answer by josmiceli(19441)  (Show Source):
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