SOLUTION: 1. The width of a rectangle is 4 inches less than its length. Its area is 12 square inches. Find the dimensions of the rectangle. 2. Find the lengths of the sides of a right tr

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: 1. The width of a rectangle is 4 inches less than its length. Its area is 12 square inches. Find the dimensions of the rectangle. 2. Find the lengths of the sides of a right tr      Log On


   

Question 858492: 1. The width of a rectangle is 4 inches less than its length. Its area is 12 square inches. Find the dimensions of the rectangle.
2. Find the lengths of the sides of a right triangle if the hypotenuse is 10 centimeters longer than the shorter leg and 5 centimeters longer than the longer leg
3.Find the lengths of the sides of a right triangle if the hypotenuse is 10 centimeters longer than the shorter leg and 5 centimeters longer than the longer leg.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the width. Then the length must be . Since length times width equals area:



Put the quadratic into standard form



Solve the quadratic for , then calculate

Hint: 6 + (-2) = 4 and 6 X -2 = -12

John

My calculator said it, I believe it, that settles it
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