SOLUTION: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2.

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Question 854421: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
area = width * length

20 = (L)(L - 8)
20 = L^2 - 8L
0 = L^2 - 8L - 20
0 = (L - 10)(L + 2)

Distance is positive, so the rectangle is 10 cm long and 2 cm wide.