SOLUTION: what is the least of three consecutive integers whose product is 120?

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Question 853475: what is the least of three consecutive integers whose product is 120?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First take the cube root of 120 to find the neighborhood of the integers.
x%5E3=120
x=4.93
Start with 4.
N=4%2A5%2A6=120
OK, that's it.
4 is the least.