SOLUTION: Find the smallest of three consecutive even integers so that four times the smallest increased by two times the largest is 32

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Question 834251: Find the smallest of three consecutive even integers so that four times the smallest increased by two times the largest is 32
Answer by DrBeeee(684) About Me  (Show Source):
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Let a,b,c represent the three consecutive even integers. Then we have
(1) a = a
(2) b = a + 2 and
(3) c = a + 4
We are given that
(4) 4*a + 2*c = 32
Put (3) into (4) and get
(5) 4a + 2(a + 4) = 32 or
(6) 4a + 2a + 8 = 32 or
(7) 6a = 32 - 8 or
(8) 6a = 24 or
(9) a = 4
Then from (2) and (3) we get
(10) b = 6 and
(11) c = 8
Check the answer with (4).
Is (4*4 + 2*8 = 32)?
Is (16 + 16 = 32)?
Is (32 = 32)? Yes
Answer: The smallest integer is 4.