You can put this solution on YOUR website! Find two consecutive odd integers that twice the larger is 15 more than 3 times the smaller.
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1st: 2x-1
2nd: 2x+1
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Equation:
2(2x+1) = 3(2x-1)+15
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4x + 2 = 6x + 12
2x = -10
x = -5
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1st: 2x-1 = -11
2nd: 2x+1 = -9
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Cheers,
Stan H.
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