SOLUTION: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third.
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Question 823138
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Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third.
Answer by
CubeyThePenguin(3113)
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consecutive positive integers: (x-1), x, (x+1)
(x-1)(x) = 11(x+1) - 22
x^2 - x = 11x - 11
x^2 - 12x + 11 = 0
(x - 11)(x - 1) = 0
The integers could be {0, 1, 2} or {10, 11, 12}.
