SOLUTION: what are three consecutive positive numbers such that the product of the first and third, minus the second,is one more than six times the third

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Question 819692: what are three consecutive positive numbers such that the product of the first and third, minus the second,is one more than six times the third
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive numbers: (x-1), x, (x+1)

(x-1)(x+1) - x = 1 + 6(x+1)
x^2 - x - 1 = 6x + 7
x^2 - 7x - 8 = 0
(x - 8)(x + 1) = 0

x is positive, so the numbers are 7, 8, and 9.