Question 805755: The product of two consecutive odd integers is 49 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The product of two consecutive odd integers is 49 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
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1st odd:: 2x-1
2nd odd: 2x+1
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Equation:
4x^2-1 = 8(4x) - 49
4x^2 -32x +50 = 0
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2x^2 - 16x + 25 = 0
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Note:: The solutions are not integers.
Please check the written statement of your problem.
Cheers,
Stan H.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
The product of two consecutive odd integers is 49 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
 or 
You can do the check!!
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