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| Question 801685:  find 5 consecutive integers whose sum of the first, third, and fifth is 99
 Answer by Cromlix(4381)
      (Show Source): 
You can put this solution on YOUR website! 5 consecutive integers: n, n + 1, n + 2, n + 3, n + 4.
 Sum of first, third and fifth = 99
 n + (n + 2) + (n + 4) = 99
 Remove brackets:
 n + n + 2 + n + 4 = 99
 Collect like terms:
 3n + 6 = 99
 3n = 99 - 6
 2n = 93
 n = 31.
 5 consecutive integers:
 31, 32, 33, 34, 35.
 Hope this helps.
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