SOLUTION: if the sum of 3 consecutive integers is 192 what is twice the middle integer
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Question 801221
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if the sum of 3 consecutive integers is 192 what is twice the middle integer
Answer by
CubeyThePenguin(3113)
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consecutive integers: (x-1), x, (x+1)
(x-1) + x + (x+1) = 192
3x = 192
x = 64
twice the middle integer = 2x = 128