SOLUTION: Find 4 consecutive integers such that the sum of the first three exceeds the fourth by 18

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Question 798920: Find 4 consecutive integers such that the sum of the first three exceeds the fourth by 18
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
X+%2B+%28X%2B1%29+%2B+%28X%2B2%29+=+%28X%2B3%29+%2B+18
Combine like terms
3X+%2B+3+=+X+%2B+21
Subtract X form both sides.
2X+%2B+3+=+21
Subtract 3 from both sides.
2X+=+18
Divide both sides by 2.
highlight%28X+=+9%29
The four consecutive integers are: 9, 10, 11 & 12