SOLUTION: Find three consecutive odd integers such that the sum of the squares of the first two is 15 less than the square of the third.

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Question 792830: Find three consecutive odd integers such that the sum of the squares of the first two is 15 less than the square of the third.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2)^2 + x^2 = (x+2)^2 - 15
x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 - 15
2x^2 - 4x + 4 = x^2 + 4x - 11
x^2 - 8x + 15 = 0
(x - 3)(x - 5) = 0

The integers could be (1, 3, 5) or (3, 5, 7).