SOLUTION: Find three consecutive integers such that three times the greatest is three less than the sum of the other two.
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Question 784794
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Find three consecutive integers such that three times the greatest is three less than the sum of the other two.
Answer by
CubeyThePenguin(3113)
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consecutive integers: (x-1), x, (x+1)
3(x+1) = (x-1) + x - 3
3x + 3 = 2x - 4
x = -7
The integers are -8, -7, and -6.