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the product of 2 consecutive odd integers is equal to 30 more than the first. Find the integers
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Let your lesser odd number be 'n'.
Then the other odd number is (n+2).
Your equation is
n*(n+2) = n + 30.
Simplify
n^2 + 2n = n + 30,
n^2 + n - 30 = 0,
(n+6)*(n-5) = 0.
The roots are -6 and 5.
You want the odd number - so, you select 5 and reject -6.
ANSWER. The numbers are 5 and 7.
Solved.
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Ignore the answer by @lynnlo, since it is incorrect.