SOLUTION: What are three consecutive even integers whose product is 4 times their sum?

Question 725104: What are three consecutive even integers whose product is 4 times their sum?
Found 2 solutions by JBarnum, Alan3354:
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
X X+2 X+4
X(x+2)(x+4)= 4(x + x+2 + x+4)
X(x^2+6x+8) =4(3x+6)
x^3+6x^2+8x=12x+24
x^3+6x^2-4x-24=0
x^2(x+6)+(-4)(x+6)=0
(x^2-4)(x+6)=0
(x-2)(x+2)(x+6)=0
X= -6, -2, 2
So there's a few possible answers
-6 -4 -2
-2 0 2
2 4 6
Lets check
-6*-4*-2= 4(-6-4-2)
-48=-48
Yes
-2*0*2= 4(-2+0+2)
0=0
Yep
2*4*6=4(2+4+6)
48=48
Yes all are correct pick which 3 numbers u want to use
This was all done on my iPhone 3G

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What are three consecutive even integers whose product is 4 times their sum?
----------------
(x-2)*x*(x+2) = 4*3x

x = 0 --> -2, 0, +2
--------------------
x^2 = 16
x = 4 --> 2, 4, 6
-----
x = -4 --> -6, -4, -2

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